July 4th is almost here and Barasti’s House of Whatever is ready to celebrate Independence Day with incredible deals, some awesome giveaways, and a huge surprise!
After a secret gig where R&B superstar Craig David entertained Barasti guests on 20th June, the popular beach bar has announced that there’s yet another surprise heading their way.
4th of July Celebrations
Seeing that its 4th of July and Independence day in the US, Barasti will be flying in talent directly from the States. The popular Beach Bar’s lips are sealed about who exactly this act might be, but they have given us a little teaser…
The only hint they’ve given is:
This American hip-hop trio has collaborated with the likes of Snoop Dog.
Are you Ready for Whatever?
If you are in the mood for a surprise then get down to Barasti’s House of Whatever this Thursday.
If we were to take a wild guess, then we’d have to say it would be De La Soul.
Is it De La Soul?
De La Soul is an American hip hop trio that came together in 1987 in the Amityville area of Long Island, New York. They are probably most well known for their wide-ranging sampling, quirky lyrics, as well as their contributions to the evolution of the jazz rap and alternative hip hop subgenres in the US. The trio is made up of Posdnuos, Trugoy and Maseo.
They have also collaborated with Snoop Dog!
This is just our guess!
This is basically the kind of suspense that is to be expected at House of Whatever throughout the summer!
House of Whatever
When: Thursday July 4
Stay tuned to Barasti’s Facebook Page for updates